Q:

Students in a statistics class conduct a survey to estimate the mean number of units students at their college are enrolled in. The students took a random sample of 50 students from their college. The students calculated a 90% confidence interval to estimate the mean number of units students at their college are enrolled in. The confidence interval was too wide to provide a precise estimate. The students are strategizing about how to produce a narrower confidence interval. True or false? The students could produce a narrower confidence interval by increasing the confidence level to 95%. True False

Accepted Solution

A:
Answer:TrueStep-by-step explanation:The margin of error of a confidence interval is given by:[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]In which z is the critical value related to the confidence level, [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.So as n increases, the margin of error decreases, that is, the interval gets narrower.The students could produce a narrower confidence interval by increasing the sample size to 100.From the explanation above, the answer is true.